eight shortest routes from London to its antipode
Great circles leaving London on eight different bearings, every one of them arriving at the same point on the far side of the world after exactly the same 20015 km. Between a point and its antipode there is no shortest path, because there are infinitely many and they are all shortest. Displace the destination by 0.4° — 52 km — and one of them wins, but only just, which is the condition an iterative solver cannot handle.
It is drawn by route-figure with
show: "antipodal-routes" — one member of a family of
9 figures
that share a generator, so the drawing above is what that generator returns when it is asked
for this one and given nothing else.
3 essays call it. Every call below passes it something, because a placement that passes nothing draws whichever member of the family the generator happens to default to rather than the one its essay argues about.
Where it is called
Changing this changes every one of these figures.
The great-circle vertex
One quantity is constant along a shortest path on a sphere, and it fixes the highest latitude that path will reach before the journey starts. That number is why polar routes exist, and it can be read off the departure bearing without tracing the route at all.
The route with no shortest path
Between a point and the point diametrically opposite there are infinitely many shortest routes and no shortest route, and the standard formula for the distance between two places stops converging in a neighbourhood of it. The failure is a property of the question rather than a defect in the answer.
Where the shortest route stops being the only one
On a sphere there is exactly one point with no shortest route from a given place: the antipode. On the ellipsoid the Earth actually is, that point is an arc — sixty-six kilometres of the antipodal meridian for a point on the equator, half a kilometre for one at 85°, and every point of it reachable by two different geodesics of exactly equal length.